设实数x.y满足x^2+y=0(0
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设实数x.y满足x^2+y=0(0设实数x.y满足x^2+y=0(0设实数x.y满足x^2+y=0(0a^x+a^y=a^x+a^(-x²)>=2[a^(x²-x)]^1/2因为x
设实数x.y满足x^2+y=0(0
设实数x.y满足x^2+y=0(0
设实数x.y满足x^2+y=0(0
a^x+a^y=a^x+a^(-x²)>=2[a^(x²-x)]^1/2
因为x²-x=(x-1/2)²-1/4>=1/4
所以a^x+a^y=a^x+a^(-x²)>=2[a^(x²-x)]^1/2>=2a^1/8
两边取loga
log a(a^x+a^y)
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