设实数x,y满足x^2+2xy-1=0则x+y的取值范围是
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设实数x,y满足x^2+2xy-1=0则x+y的取值范围是设实数x,y满足x^2+2xy-1=0则x+y的取值范围是设实数x,y满足x^2+2xy-1=0则x+y的取值范围是x^2+2xy-1=0(x
设实数x,y满足x^2+2xy-1=0则x+y的取值范围是
设实数x,y满足x^2+2xy-1=0则x+y的取值范围是
设实数x,y满足x^2+2xy-1=0则x+y的取值范围是
x^2+2xy-1=0
(x+y)^2=y^2+1>=1
所以x+y>=1或x+y
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