设实数x,y满足x^2+2xy-1=0,则x+y的取值范围是
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设实数x,y满足x^2+2xy-1=0,则x+y的取值范围是设实数x,y满足x^2+2xy-1=0,则x+y的取值范围是设实数x,y满足x^2+2xy-1=0,则x+y的取值范围是∵x2+2xy-1=
设实数x,y满足x^2+2xy-1=0,则x+y的取值范围是
设实数x,y满足x^2+2xy-1=0,则x+y的取值范围是
设实数x,y满足x^2+2xy-1=0,则x+y的取值范围是
∵x2+2xy-1=0
∴(x+y)2=1+y2≥1
则x+y≥1或x+y≤-1
故x+y的取值范围是(-∞,-1]∪[1,∞)
故答案为:(-∞,-1]∪[1,∞)
希望对你能有所帮助.
设x+y=k,则y=k-x
即有
x²+2x(k-x)-1=0
化简得
x²-2kx+1=0
△=4k²-4≥0
所以k≥1或k≤-1
∴x+y≥1或x+y≤-1
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