80!=1*2*3*······*79*80,这个数的末尾共有()个0
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/27 02:45:18
80!=1*2*3*······*79*80,这个数的末尾共有()个080!=1*2*3*······*79*80,这个数的末尾共有()个080!=1*2*3*······*79*80,这个数的末尾共
80!=1*2*3*······*79*80,这个数的末尾共有()个0
80!=1*2*3*······*79*80,这个数的末尾共有()个0
80!=1*2*3*······*79*80,这个数的末尾共有()个0
80!=1*2*3*······*79*80,这个数的末尾共有(16)个0
出现10的倍数的时候会诞生一个0,总共是8个0
出现末尾是5的数和1个偶数的积也会诞生1个0
因为偶数有40个,而末尾是5的数才8个,所以每个5都能配到偶数.
所以一共是8+8=16个0
一个因数2和一个因数5可以在结果末尾生成一个0，80/5=16，共有16个因数5，以及80/2=40，,40个因数2，所以有末尾16个0
16个零
因数2的个数充足，不用考虑。
80\5 = 16，即至少有16个数含1个因数5
80\25 = 2 ，即至少有2个数含2个因数5
综上，1乘到80，共含有16+2=18个因数5。
则末尾共有(18)个0
急·····················1+2+3+...+999=?
80!=1*2*3*······*79*80,这个数的末尾共有()个0
1+2++3+··········+10000=
1 2 3 4 ·····7 ·······10 ········?1 3 5 7 ·····?······?··········290 1 4 9 ·····?······?··········?
变态数学题·······方程一道············x+2y+3z=1x=y+12x+3y+5z=2方程组············要过程············我解了之后总觉得无解·····
在等腰三角形ABC中,AB=AC.求证1、∠BAD=∠CAE 2、如果AD=AE,那么BD=CE吗?急啊·························································
1/3+2/3=1,但0.333···+0.666···=0.999···,为神马?额······谁能解释一下······
2[4/3y—（2/3y—1/2）]=3/4y急·································!1
8+11+14+17+20+·······+305 数学计算题.呜呜呜1+2+3+4+···················+98+99+100+99+98+···············+3+2+1
300*1+300*2+300*3+···················300*30=?这种题目怎么换算的急,
秦始皇和汉武帝各自的功劳是?（用1·······2·······3··········来说）
1乘2+2乘3+·········100乘101=多少
俗语和名句的填空1······,自知之明.2······,行必果.3工欲善其事,······.4临渊羡鱼,······.5非学无以广才,······.6······,福兮祸之所伏.7项庄舞剑,······.8······,人以群
1+2+3+4+······+78+79+801/2+1/6+1/12+1/20+······+1/72+1/90100-99+98-97+96-······+4-3+2-11000-1-2-3-4-······-78-79-801/15+2/15+······+13/15+14/15注：例 1/15 就是 十五分之一
纸鹤数量的意义比如说 1只纸鹤,代表······· 2只纸鹤,代表······· ······················· ···························· ·················· 越多越好,
（1994+1992+······+4+2）—（1+3+5+······+1991+1993）=（ ）
（1+3+5++7+9······+2011）-（2+4+6+8······+2012）=
已知三个角1,2,3满足：1与2互补,2与3互余,试求1-3的大小!·································