已知f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4,则f(2014)=已知f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4,则f(2014)=

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已知f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4,则f(2014)=已知f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)

已知f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4,则f(2014)=已知f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4,则f(2014)=
已知f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4,则f(2014)=
已知f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4,则f(2014)=

已知f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4,则f(2014)=已知f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4,则f(2014)=
f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4
=-cos(πx/2)-sin(πx/2)
f(2014)=-cos(1007π)-sin(1007π)=-cos(π)-sin(π)=1