sin(π+α)=1/2,求sin(2π-α)-cot(α-π)cosα
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sin(π+α)=1/2,求sin(2π-α)-cot(α-π)cosαsin(π+α)=1/2,求sin(2π-α)-cot(α-π)cosαsin(π+α)=1/2,求sin(2π-α)-cot(
sin(π+α)=1/2,求sin(2π-α)-cot(α-π)cosα
sin(π+α)=1/2,求sin(2π-α)-cot(α-π)cosα
sin(π+α)=1/2,求sin(2π-α)-cot(α-π)cosα
sin(2π-α)=-sinα
-cot(α-π)=-1/tanα
sin(π+α)=1/2得-cosα=1/2,即cosα=-1/2,
原式=-sinα-cos2α/sinα
又由sin2+cos2=1得,sinα=±3/4,
又因为cos为负
则sinα=3/4
故原式等于-12/13
好久没算过这类题了,也不知对不对
不出意外的话应该对了
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