化简:(sin^2α-tan^2α)/(sin^2α·tan^2α)
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化简:(sin^2α-tan^2α)/(sin^2α·tan^2α)化简:(sin^2α-tan^2α)/(sin^2α·tan^2α)化简:(sin^2α-tan^2α)/(sin^2α·tan^2
化简:(sin^2α-tan^2α)/(sin^2α·tan^2α)
化简:(sin^2α-tan^2α)/(sin^2α·tan^2α)
化简:(sin^2α-tan^2α)/(sin^2α·tan^2α)
(sin²α-tan²α)/(sin²α·tan²α)
=(sin²α-sin²α/cos²α)/(sin²α·sin²α/cos²α)
=(sin²α*cos²α-sin²α)/(sin²α·sin²α)
=(cos²α-1)/sin²α
=-sin²α/sin²α
=-1
(sin^2α-tan^2α)/(sin^2α·tan^2α)
=[sin^2α(1-1/cos^2α)]/[(sin^2α*tan^2α)]
=[(1-1/cos^2α)]/[(tan^2α)]
=[(cos^2α-1)/cos^2α] *1/tan^2α
=-sin^2α/sin^2α
=-1
你好
tan^2α=sin^2α/cos^2α
原式上下同除以sin^2α得
(1-1/cos^2α)/(sin^2α/cos^2α) 上下同乘以cos^2α
=(cos^2α-1)/sin^2α
=-sin^2α/sin^2α
=-1
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你好
tan^2α=sin^2α/cos^2α
原式上下同除以sin^2α得
(1-1/cos^2α)/(sin^2α/cos^2α) 上下同乘以cos^2α
=(cos^2α-1)/sin^2α
=-sin^2α/sin^2α
=-1
【数学辅导团】为您解答,
不理解请追问
理解请及时选为满意回答!(*^__^*)谢谢!
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