设lim[(x^2+2x+3)^1/2-ax]=b,求a,b
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设lim[(x^2+2x+3)^1/2-ax]=b,求a,b设lim[(x^2+2x+3)^1/2-ax]=b,求a,b设lim[(x^2+2x+3)^1/2-ax]=b,求a,b解题目欠完整:x→?
设lim[(x^2+2x+3)^1/2-ax]=b,求a,b
设lim[(x^2+2x+3)^1/2-ax]=b,求a,b
设lim[(x^2+2x+3)^1/2-ax]=b,求a,b
解
题目欠完整:x→?
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设lim[(x^2+2x+3)^1/2-ax]=b,求a,b
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