求-log2 log2 √√√2的值如题,这个√√√2是怎么回事...

求-log2 log2 √√√2的值如题,这个√√√2是怎么回事... log2[√(7/48)]+log2(12)-log2(√42) y=√ log2[log2(log2x)] 的定义域是什么 log2(下标)√2的值是? ? ? ? ? ? ? Log2√（7/48） +log2 12 -（1/2）log2 42要详细点的额 log2 √7/24+log2 12-log442 求f(x)=(log2(x/4))*(log2(x/2)),x∈[√2,8]的值域 求函数y=(log2(x/3))(log2(x/4))在区间《2√2,8》上的最值 log2√2等于多少 化简算式log2^√7/48+log2^12-1/2log2^42+1/2^log2^3 求值：log2√(7/48)+log2(12)-1/2log2(42)-1 这道题我算来算去算不对 log2底√1/48+log2底12-1/2log2底24等于? 计算log2 √(48/7)-log2 12+(1/2)log2 42-1 log2（√1/48）+log2 12-1/2log2 （24）-1/3 求值log2^3+log2^√3/log2^9-log2^√3 求值【log2^3+log2^√3/log2^9-log2^√3】-2013^0 求√log2(3-4x)定义域. log2(1+根号2+根号3）+log2（1+根号2-根号3）=中有一步是怎样来的解：log2(1+根号2+根号3）+log2（1+根号2-根号3）=log2[(1+√2+√3)(1+√2-√3)]=log2[(1+√2)²-(√3)²]=log2[2√2]=log2[2^(3/2)]=3/2这里log2[2