log2(1+根号2+根号3）+log2（1+根号2-根号3）=中有一步是怎样来的解：log2(1+根号2+根号3）+log2（1+根号2-根号3）=log2[(1+√2+√3)(1+√2-√3)]=log2[(1+√2)²-(√3)²]=log2[2√2]=log2[2^(3/2)]=3/2这里log2[2

log2(1+根号2+根号3）+log2（1+根号2-根号3）= log2(1+根号2+根号3)+log2(1+根号2 -根号3） log2+根号3（2-根号3） 根号下[(log2^3)^2-4log2^3+4]+log2^(1/3) 化简根号下[(log2^3)^2-4log2^3+4]+log2^(1/3) log2(1+根号2+根号3）+log2（1+根号2-根号3）=中有一步是怎样来的解：log2(1+根号2+根号3）+log2（1+根号2-根号3）=log2[(1+√2+√3)(1+√2-√3)]=log2[(1+√2)²-(√3)²]=log2[2√2]=log2[2^(3/2)]=3/2这里log2[2 log2-根号3(2+根号3) (log3^4+log5^2)(log2^9+log2^根号3) 计算log2.5（6.25）+lg1/100+In根号下e+2[1+log2(3)]2.5是下标,[1+log2(3)]是上标,(3)是上标 log2底根号5/56+log2(14)-1/2log2(35)答案是-1/2 log2(根号下7/48)+log2(12)-1/2log2(42)-1=? log2根号7/48+log2^12-1/2log2^42-1= 根号下{[log2 （5)]^2-4log2(5)+4}+log2(1/5) 计算 根号下[(log2 5)^2-4log2 5+4]+log2 1/5 log根号2^（x-5）log2^(x-1) log2根号2的值 log2 根号2怎么计算? log2根号2怎么算?