log2(1+根号2+根号3)+log2(1+根号2-根号3)=
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log2(1+根号2+根号3)+log2(1+根号2-根号3)=log2(1+根号2+根号3)+log2(1+根号2-根号3)=log2(1+根号2+根号3)+log2(1+根号2-根号3)=log2
log2(1+根号2+根号3)+log2(1+根号2-根号3)=
log2(1+根号2+根号3)+log2(1+根号2-根号3)=
log2(1+根号2+根号3)+log2(1+根号2-根号3)=
log2(1+根号2+根号3)+log2(1+根号2-根号3)
=log2[(1+√2+√3)(1+√2-√3)]
=log2[(1+√2)²-(√3)²]
=log2[2√2]
=log2[2^(3/2)]
=3/2
祝愉快!
log2(1+根号2+根号3)+log2(1+根号2-根号3)=
log2(1+根号2+根号3)+log2(1+根号2 -根号3)
log2+根号3(2-根号3)
根号下[(log2^3)^2-4log2^3+4]+log2^(1/3)
化简根号下[(log2^3)^2-4log2^3+4]+log2^(1/3)
log2(1+根号2+根号3)+log2(1+根号2-根号3)=中有一步是怎样来的解:log2(1+根号2+根号3)+log2(1+根号2-根号3)=log2[(1+√2+√3)(1+√2-√3)]=log2[(1+√2)²-(√3)²]=log2[2√2]=log2[2^(3/2)]=3/2这里log2[2
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log2 根号2怎么计算?
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