已知log2^64 +log2^x =5 ,则x的值是?

已知log2^64 +log2^x =5 ,则x的值是? log2^(x^log2^x)=? log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5) log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5) [log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204 解2log2^(x-5)=log2^(x-1)+1 log4(log2^x)=log2(log4^x)求log2^x 已知集合A={x|log2(-x) log2 (x+1)+log2 x=log6 log2 5 x log2 5等于log2 25还是什么? log2(-x)=x+ 已知log2(x^2)=log2(根号2-1)-log2(根号2+1),求x+1/x log2 (5-x) log2 (5-x) log2(5-x) log2(5-x) log2(x)=-1 log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1