P(x)=ax4+x3-bx2-4x+c If p(x)increases without bound as x increases without bound,then,as x decreases without bound,p(x)A)increases without boundB)decreases without bound C)approaches zero from above the x-axisD)approaches zero from below the x-axisE)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/27 14:24:45
P(x)=ax4+x3-bx2-4x+c If p(x)increases without bound as x increases without bound,then,as x decreases without bound,p(x)A)increases without boundB)decreases without bound C)approaches zero from above the x-axisD)approaches zero from below the x-axisE)
P(x)=ax4+x3-bx2-4x+c If p(x)increases without bound as x increases without bound,then,as x decreases without bound,p(x)
A)increases without bound
B)decreases without bound
C)approaches zero from above the x-axis
D)approaches zero from below the x-axis
E)cannot be determined
P(x)=ax4+x3-bx2-4x+c If p(x)increases without bound as x increases without bound,then,as x decreases without bound,p(x)A)increases without boundB)decreases without bound C)approaches zero from above the x-axisD)approaches zero from below the x-axisE)
P(x)= ax4 + x3-bx2-4x + c如果P(x)随x上升而无限上升,同样X无限减少,那么P(x)
A)无限上升
B)无限下降
C)从大于零接近x轴
D)从小于零接近x轴
E)不能确定的
应该选(A) 推得参数a大于零,当X绝对值无限大时,考虑四次方即可,a>0,所以无限增长
P(x)= ax4 + x3-bx2-4x + c如果P(x)的上涨,而没有被约束的x的上涨,而没有捆绑,然后,随着x减少没有捆绑,P(x)
A)上涨,而没有束缚
B)降低无约束
C)从上面接近零的x轴
D)从下面接近零的x轴
E)不能确定的
数学这东西很浮云 不学没什么关系 实在不行就去问老师吧