已知cos(π/2 +α)=3/5,求[sin(α+ 3π/2)*sin(3π/2 -α)*tan²(2π-α)*tan(π-α)][sin(α+ 3π/2)*sin(3π/2 -α)*tan²(2π-α)*tan(π-α)]÷[cos(π/2 -α)*cos(π/2 +α)]的值

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/17 10:37:46
已知cos(π/2+α)=3/5,求[sin(α+3π/2)*sin(3π/2-α)*tan²(2π-α)*tan(π-α)][sin(α+3π/2)*sin(3π/2-α)*tan

已知cos(π/2 +α)=3/5,求[sin(α+ 3π/2)*sin(3π/2 -α)*tan²(2π-α)*tan(π-α)][sin(α+ 3π/2)*sin(3π/2 -α)*tan²(2π-α)*tan(π-α)]÷[cos(π/2 -α)*cos(π/2 +α)]的值
已知cos(π/2 +α)=3/5,求[sin(α+ 3π/2)*sin(3π/2 -α)*tan²(2π-α)*tan(π-α)]
[sin(α+ 3π/2)*sin(3π/2 -α)*tan²(2π-α)*tan(π-α)]÷[cos(π/2 -α)*cos(π/2 +α)]的值

已知cos(π/2 +α)=3/5,求[sin(α+ 3π/2)*sin(3π/2 -α)*tan²(2π-α)*tan(π-α)][sin(α+ 3π/2)*sin(3π/2 -α)*tan²(2π-α)*tan(π-α)]÷[cos(π/2 -α)*cos(π/2 +α)]的值

已知√3sinα+cosα=2/3,求cos(2α-π/3) 已知tanα=2求(3cosα+5sinα)/(sinα-cosα) 已知cos(π/6-α)=√3/3,求cos[(5π/6)+α]-sin^2(α-π/6) 已知sin(3π+α)=2cos(α-4π)求cos(π/2 -α)+5sin(π/2 +α)/2cos(π+α)-sin(-α) 【三角函数】已知sin(α-π)=2cos(2π-α),求[sin(π-α)+5cos(2π-α)]/[3cos(π-α)-sin(-α)] 已知cos(α+β)=12/13,cos(2α+β)=3/5,α∈(0,π/2),求cosα的值. 已知α,β∈(0,π),且cos(2α+β)-2cos(α+β)cosα=3/5,求sin2β的值 已知cos(α+β)=12/13,cos(2α+β)=3/5,若β∈(0,π/2),求cosα的值. 已知cosα/2=-12/13,求cosα. 已知cosα=4/5,α∈(3π,2π),求tanα 求值:已知sinθ+cosθ=1/5,已知θ∈(0,π).求(1)sinθ*cosθ(2)sinθ-cosθ(3)tanθ 已知cos=3/5,α∈(-π/2,0)求sin(α-π/6) 已知0<α<π/2,且3sinα=4cosα求(sin^2α+2sinαcosα)/(3cos^2α-1)求cos^2α+sinαcosα 锐角α、β满足α+β=3/4π,求cos²α+cos²β+√2cosαcosβ的值1.锐角α、β满足α+β=3/4π,求cos²α+cos²β+√2cosαcosβ的值2.已知tan(α/2)=1/4tan(β/2),求证:tan[(β-α)/2]=3sinα/(5-3cosα) 已知cosα=-八分之十七,α属于(π,二分之三派),求cos(α-六分之π)改为:已知cosα=8/17,α属于(π,3π/2),求cos(α- π/6) 1.已知cosα=12/13,α∈(3π/2,2π),求cos(α+π/4).2.cos(α+β)=1/3,则(sinα-sinβ)^2+(cosα+cosβ)^2=?3.已知sinα=(√5)/5,sinβ=(√10)/10,α、β都是锐角,求cos(α+β)及α+β的值.4.已知锐角α、β满足sinα=(√5)/5,cosβ(√10)/1 已知cos(π/3-α)=根号3/3,求cos(2π/3+α)+cos2(7π/6+α) 已知cos(π/4 - α)=- 3/5,α∈(π/2,π),求cosα