1-2x+1/4+2x+1/3=10x+1/12

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1-2x+1/4+2x+1/3=10x+1/121-2x+1/4+2x+1/3=10x+1/121-2x+1/4+2x+1/3=10x+1/121-2x+1/4+2x+1/3=10x+1/121+1/

1-2x+1/4+2x+1/3=10x+1/12
1-2x+1/4+2x+1/3=10x+1/12

1-2x+1/4+2x+1/3=10x+1/12
1-2x+1/4+2x+1/3=10x+1/12
1+1/4+1/3=10x+1/12
1+3/12+4/12=10x+1/12
1+7/12=10x+1/12
1+7/12-1/12=10x
1+1/2=10x
3/2=10x
3/20=x

1-2x+1/4+2x+1/3=10x+1/12
1+1/4+1/3=10x+1/12
1+3/12+4/12=10x+1/12
1+7/12=10x+1/12
1+7/12-1/12=10x
1+1/2=10x
x=3/20

1-2x+1/4+2x+1/3=10x+1/12
1+1/4+1/3-1/12=10x
3/2=10x
x=3/20

*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || X+X+X+(X-1)+(X-2)+(X-3)+(X-4)=10(X-3)+(X-4) 一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X 1+x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11+x^12=97.8x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11+x^12=97.8 好多年没有用过过数学公式了 想不起来怎么算了 想知道 X值是多少 已知x=2π+1求 |x-1|+|x-2|+|x-3|+|x-4|+|x-5|+|x-6|+|x-7|+|x-8|+|x-9|+|x-10| 已知x=2π+1.求(X-1)+(X-2)+(X-3)+(X-4)+(X-5)+(X-6)+(X-7)+(X-8)+(X-9)+(X-10) 1+x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11=17.7这个方程怎么样求解? (x-1)/(x+3x+2)+6/(2+x-x)-(10-x)/(4-x) (x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3) x(x+1)+(x+2)+(x+3)+(x+4)+(x+5) = 27求x 1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550必须用解方程 解方程(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=1 x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7 x=? x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002 xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 写过程x(x-1)+2x(x+1)-3x(2x-5)-x(3x-2)+2x(2-x)=-5x(x-2)-4 1x()+2x()+3x()+4x()+5x()+6x()+7x()+8x()加9x()+10x()=1980 1X?+2X?+3X?+4X?+5X?+6X?+7X?+8X?+9X?+10X?=1980求?是多少