若实数x,y满足y

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若实数x,y满足y若实数x,y满足y若实数x,y满足yyy☞x²≤2x+3☞(x-3)(x+1)≤0即:-1≤x≤3进而:0≤y≤1画出可行域y/x-12?y/x-1

若实数x,y满足y
若实数x,y满足y

若实数x,y满足y
y

y<=2x+3,y=x^2,
☞x²≤2x+3
☞(x-3)(x+1)≤0
即:-1≤x≤3
进而:0≤y≤1
画出可行域
y/x-12?y/x-12?还是y/(x-12)?

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