log2(4*-x+1)怎么等于log2(4*x+1)-2x
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/23 00:02:30
log2(4*-x+1)怎么等于log2(4*x+1)-2xlog2(4*-x+1)怎么等于log2(4*x+1)-2xlog2(4*-x+1)怎么等于log2(4*x+1)-2x
log2(4*-x+1)怎么等于log2(4*x+1)-2x
log2(4*-x+1)怎么等于log2(4*x+1)-2x
log2(4*-x+1)怎么等于log2(4*x+1)-2x
log2(4*-x+1)怎么等于log2(4*x+1)-2x
log2(3)×log2(4)=log2(7)?log2(3)×log2(4)=log2(7)吗?log2(1/49)+log2(1/16)+log2(1/27)等于多少呢?帮个忙!
log2 4+log2 (x+2)怎么算?log2 4+log2 (x+2)=log2 (4x+8)
(log2) ^2 - log5 *log20课本上 等于 (log2)^2 +(1+log2)(1-log2) = 1;(log2)^2 +(1+log2)(1-log2) 是怎么来的?
【x】表示不超过实数x的最大整数,则【log2 1]+[log2 2]+[log2 3]+.+[log2 2012]等于?
log2 5 x log2 5等于log2 25还是什么?
[log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204
解不等式log2(4x+8)>log2(2x+1)
谁能帮我解一下:log2(x + 1) = 4 - log2(x + 1)log2(x + 1) = 4 - log2(x + 1)
怎么解log2^1/4
解方程:log2(x+4)+log2(x-1)=1+log2(x+8)
log2^x怎么算
化简:(log2(x/4))*(log2(x/2))
|[log2(x)]^2-3log2(x)+1|
log2(x+1)>log2(3-x)
log2 (x+1)+log2 x=log6
log2(x+1)=3怎么解
log2(4^x+4)