x2+3x+2分之x-1减去x2-x-2分之6减去x2-4分之x-10x-1/x2+3x+2减去6/x2-x-2减去x-10/x2-4

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/22 15:29:19
x2+3x+2分之x-1减去x2-x-2分之6减去x2-4分之x-10x-1/x2+3x+2减去6/x2-x-2减去x-10/x2-4x2+3x+2分之x-1减去x2-x-2分之6减去x2-4分之x-

x2+3x+2分之x-1减去x2-x-2分之6减去x2-4分之x-10x-1/x2+3x+2减去6/x2-x-2减去x-10/x2-4
x2+3x+2分之x-1减去x2-x-2分之6减去x2-4分之x-10
x-1/x2+3x+2减去6/x2-x-2减去x-10/x2-4

x2+3x+2分之x-1减去x2-x-2分之6减去x2-4分之x-10x-1/x2+3x+2减去6/x2-x-2减去x-10/x2-4
=(x-1)/[(x+1)(x+2)]-6/[(x+1)(x-2)]-(x-10)/[(x-2)(x+2)]
=[(x-1)(x-2)-6(x+2)-(x-10)(x+1)]/[(x+1)(x+2)(x-2)]
=[(x2-3x+2)-(6x+12)-(x2-9x-10)]/[(x+1)(x+2)(x-2)]
=[x2-3x+2-6x-12-x2+9x+10]/[(x+1)(x+2)(x-2)]
=0/[(x+1)(x+2)(x-2)]
=0

什么啊,相当混乱的说法,有很多理解方法

x2+3x+2分之x-1减去x2-x-2分之6减去x2-4分之x-10
=(x-1)/(x+1)(x+2)-6/(x-2)(x+1)-(x-10)/(x+2)(x-2)
={(x-1)2(x-2)-6(x+2)(x-1)-(x-10)(x2-1)}/(x2-1)(x2-4)
=-8x/(x2-1)(x2-4)

多种理解方法