1/3x+1/5=x/2
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1/3x+1/5=x/21/3x+1/5=x/21/3x+1/5=x/2你好:1/3x+1/5=1/2x1/5=1/2x-1/3x1/5=1/6xx=1/5×6x=6/5按照楼上那位的解法,你那个“1
1/3x+1/5=x/2
1/3x+1/5=x/2
1/3x+1/5=x/2
你好:
1/3x+1/5=1/2x
1/5=1/2x-1/3x
1/5=1/6x
x=1/5×6
x=6/5
按照楼上那位的解法,你那个“1/3x”的三分之一是一元系数啊?你这是几年级的题目?
乍一看这个题目,以为第一个x是在分母上的,那就不是那个解法啦,就是一元二次方程了,两个解坑爹到极点啊……
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x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4
x^5-x^4+x^3-x^2+x-1
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(x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3)
解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)
x(x-2)-2x(x+1)-3x(x-5) 其中x=负½
x(x+1)+(x+2)+(x+3)+(x+4)+(x+5) = 27求x
x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7 x=?
5x(3x-2)-(x+1)
写过程x(x-1)+2x(x+1)-3x(2x-5)-x(3x-2)+2x(2-x)=-5x(x-2)-4
计算:[(x+2)/(x+3) - (x+1)/(x+2) + (x+4)/(x+5) - (x+3)/(x+4) / (x^2 + 7x + 13)/(x^2 + 8x + 15)
[(x+2)/(x+3)-(x+1)/(x+2)+(x+4)/(x+5)-(x+3)/(x+4)]/[(x的平方+7x+13)/(x的平方+8x+15)]