1/(x-3)+1/(x-3)=4/(x²-9)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/29 10:08:31
1/(x-3)+1/(x-3)=4/(x²-9)1/(x-3)+1/(x-3)=4/(x²-9)1/(x-3)+1/(x-3)=4/(x²-9)1/(x-3)+1/(x-
1/(x-3)+1/(x-3)=4/(x²-9)
1/(x-3)+1/(x-3)=4/(x²-9)
1/(x-3)+1/(x-3)=4/(x²-9)
1/(x-3)+1/(x-3)=4/(x²-9)两边同乘 x²-9 得 (x+3)+(x+3)=4
x+3+x+3=4
2x+6=4
2x=-2
x=-1
经检验:……
∴……
经检验,是原方程的根。 你保证题目没错吗? 亲,*^__^* ,满意请采纳,不懂请追问,谢谢!
两边同乘以x²-9,得
x-3+x+3=4
2x=4
x=2
经检验x=2是方程的根。
解由题得1/(x-3)+1/(x-3)=2/(x-3)=4/(x平方-9)再交叉相乘得x²-2x-3=0即(x-3)(x+1)=0所以x=3或-1
*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X
(x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3)
x(x+1)+(x+2)+(x+3)+(x+4)+(x+5) = 27求x
X+X+X+(X-1)+(X-2)+(X-3)+(X-4)=10(X-3)+(X-4)
x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7 x=?
x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002
写过程x(x-1)+2x(x+1)-3x(2x-5)-x(3x-2)+2x(2-x)=-5x(x-2)-4
x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4
[3/x]-[4/x-1]=6/x-x²
[3/x]-[4/x-1]=6/x-x²
(x+1)(x+2)(x+3)(x+4)=24
(x-1)(x-2)(x-3)(x-4)=48
(x+1)(x+2)(x+3)(x+4)=24
x-1+x+2+x/3+4x=77
1+x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11+x^12=97.8x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11+x^12=97.8 好多年没有用过过数学公式了 想不起来怎么算了 想知道 X值是多少
已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^+x^6+x^7+x^8的值
如果1+x+x^2+x^3=0,求x+x^2+X^3+x^4+x^5+x^6+x^7+x^8的值,