3x-y+z=4 2x+3y-2z=12{3x-y+z=4,2x+3y-2z=12,3x+2y=66 还有一题 a+b+c=-6a-b+c=-84a+2b+c=-11
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/17 19:30:03
3x-y+z=42x+3y-2z=12{3x-y+z=4,2x+3y-2z=12,3x+2y=66还有一题a+b+c=-6a-b+c=-84a+2b+c=-113x-y+z=42x+3y-2z=12{
3x-y+z=4 2x+3y-2z=12{3x-y+z=4,2x+3y-2z=12,3x+2y=66 还有一题 a+b+c=-6a-b+c=-84a+2b+c=-11
3x-y+z=4 2x+3y-2z=12
{3x-y+z=4,2x+3y-2z=12,3x+2y=66
还有一题 a+b+c=-6
a-b+c=-8
4a+2b+c=-11
3x-y+z=4 2x+3y-2z=12{3x-y+z=4,2x+3y-2z=12,3x+2y=66 还有一题 a+b+c=-6a-b+c=-84a+2b+c=-11
3x-y+z=4 (1)
2x+3y-2z=12 (2)
3x+2y=66 (3)
(1)*2+(2)
8x-y=20 (4)
(3)+(4)*2
x=106/19 代入(4) 得y=243/76
一起代入(1)得z=-725/76
方法同一.直接上答案a=-7/3 b=1 c=-11/3
12合并:1*2+2
8x+Y=16 4
4*2-3
可以算x带入3可算y
…………
z=-3x+y 带入第二式得:2x+3y-2(-3x+y)=12 y=8x 再带入第三式会了吧,呵呵
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
x+2y=3x+2z=4y+z 求x:y:z
x+y/2=z+x/3=y+z/4 x+y+z=27
3x-y+z=4,2z+3y-z=12,x+y+z=6的解
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
X=3z X+y+z=12 X+2y-2z=10
2x+z=10 x+y-z=4 3x-y-z=0
解方程组{3x+y-z=4,2x-y+3z=12,x+y+z=6}
解方程组2x+3y-z=12,3x-y+z=4,x+y+z=6
{3x-y+z=4,2x+3y-z=12,x+y+z=6
3x-y+z=4,2x+3y-z=12,x+y+z=6
3x - y + Z=4{ 2x + 3y - Z=12X + Y + Z = 6
3x-y+z=4, 2x+3y-z=12, x+y+z=6
3x-y+z=4 2x+3y-z=12 x+y+z=6
2x+3y-z=12 3x-y+z=4 x+y+z=6
x:y:z=2:3:4,x+2y-z=12,求x,y,z
x-4y+z=-3 2x-y+z=18 x-y-z=12