解出x、y.①x∧2＋y∧2－6x＋4y＋12＝0②x∧2＋y∧2－14x－2y＋14＝0.

解出x、y.①x∧2＋y∧2－6x＋4y＋12＝0②x∧2＋y∧2－14x－2y＋14＝0. 把(x+y),(x-y)个作为一个整体合并同类项1,7(x+y)-2(x+y)-4(x+y)+2(x+y)2,(x-y)²＋2(x-y)－(x-y)－2(x-y)² 【2(x-y)(x-y)(x-y)-8(x-y)(x-y)(x+y)+6y(x-y)(x-y)]/2(x-y)(x-y) 把6x（x－y）的平方＋3（y－x）的立方分解因式我知道答案是6x(x-y)^2+3(y-x)^3=6x(x-y)^2-3(x-y)^3=3(x-y)^2[2x-(x-y)]=3(x-y)^2(x+y)可为什么=6x(x-y)^2-3(x-y)^3=3(x-y)^2[2x-(x-y)] [（x＋2y）（x－2y）＋4（x－y）²]÷6x （2x＋y)²－y(y＋4x)－8x等于? y(x＋y)＋(x－y)²－x²－2y² 先化简,再求值:[(x＋y)(x-y)-(x-y)²+2y(x+y)]除4y,其中x=2,y=1 x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 计算：（1）2/（x＋y）＋4y/x²－y²（2）x²/x＋y－x＋y [(x+y)(x-y)-(x-y)²+2y(x-y)]÷4y 已知x和y满足x＋3y＋|3x－y|＝19,2x＋y＝6,求x,y的值 设x,y满足x＋3y＋|3x－y|＝19,2x＋y＝6则X= Y= (x－y)∧4－2(x－y)²＋1 已知x－y＝1,y≠0,求｛(x＋2y)²＋（2x＋y）(x＋4y)－3(x＋y）（x－y)｝÷y的值. 解二元一次方程组：3(x+y)-4(x-y)=4,x+y/2+x-y/6+1x+y/2+x-y/6+1=1 X＋y＝2/3 x∧2＋y∧2＝1联立解X和y 解方程组,①5x＋y=2 ②x－3y=4