CD=s AB垂直BC 求AB

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CD=sAB垂直BC求ABCD=sAB垂直BC求ABCD=sAB垂直BC求ABBC/SIN(β)=CD/SIN(180-(α+β))BC=CD*SIN(β)/SIN(180-(α+β))=s*SIN(

CD=s AB垂直BC 求AB
CD=s AB垂直BC 求AB

CD=s AB垂直BC 求AB
BC/SIN(β)=CD/SIN(180-(α+β))
BC=CD*SIN(β)/SIN(180-(α+β))
=s*SIN(β)/SIN(α+β)
AB=BC*TAN(θ)
=(s*SIN(β)/SIN(α+β))*TAN(θ)
=s*TAN(θ)*SIN(β)/SIN(α+β)

BC=DC/sin(π-α-β)
=s/sin(α+β)
AB=BCtanθ
=s tanθ/sin(α+β)

这是相似三角形,我没学,所以解不出来,抱歉