高数求极限.x趋向于零,lim(sin^2x-x^2cos^2x)/x^2sin^2x ,高数求极限.x趋向于零,lim(sin^2x-x^2cos^2x)/x^2sin^2x ,
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/18 13:09:30
高数求极限.x趋向于零,lim(sin^2x-x^2cos^2x)/x^2sin^2x,高数求极限.x趋向于零,lim(sin^2x-x^2cos^2x)/x^2sin^2x,高数求极限.x趋向于零,
高数求极限.x趋向于零,lim(sin^2x-x^2cos^2x)/x^2sin^2x ,高数求极限.x趋向于零,lim(sin^2x-x^2cos^2x)/x^2sin^2x ,
高数求极限.x趋向于零,lim(sin^2x-x^2cos^2x)/x^2sin^2x ,
高数求极限.x趋向于零,lim(sin^2x-x^2cos^2x)/x^2sin^2x ,
高数求极限.x趋向于零,lim(sin^2x-x^2cos^2x)/x^2sin^2x ,高数求极限.x趋向于零,lim(sin^2x-x^2cos^2x)/x^2sin^2x ,
sinx=x-1/6x^3+o(x^3) 则sin^2x=x^2-1/3x^4+o(x^4)
cosx=1-x^2/2+o(x^4) cos^2x=1-x^2+o(x^4)
那么分子就是sin^2x-x^2cos^2x=x^2-1/3x^4+o(x^4)-[x^2-x^4+o(x^4)]=2/3x^4+o(x^4) 所以结果是2/3
或者sin^2x-x^2cos^2x=(sinx+xcosx)(sinx-xcosx)
那么原式=lim(x-->0)(sinx+xcosx)/x*lim(x-->0)sinx-xcosx/x^3=2limxsinx/3x^2=2/3
高数求极限.x趋向于零,lim(sin^2x-x^2cos^2x)/x^2sin^2x ,高数求极限.x趋向于零,lim(sin^2x-x^2cos^2x)/x^2sin^2x ,
求lim [sin(x^2-1)]/(x-1) x趋向于1的极限.
求极限lim(x趋向于0)ln(1+x^2)/sin(1+x^2)
求下列极限.lim(n趋向于无穷大)(2x次方)*(sin*1/2x次方)
求x趋向于pai时 lim[sin/(pai-x)]的极限
求极限(x趋向于0时)lim[sinx-sin(sinx)]/(sinx)^3
lim x趋向无穷 sinπx 的极限 与 lim x趋向正无穷 sinπx 的极限
证明极限x趋向于0,y趋向于0,lim(sinxsiny)/(sin∧2x+sin∧2y)不存在
洛必达法则求极限:1.lim当x趋向于零正时x^x的极限;2.lim当x趋向于0时(1-x)^(1/x)的极限,
求极限lim(x趋向于1)(x-1)tan(x^2-1)/sin(x-1)lnx
帮忙解决下列极限计算lim(ln Sin x / ln x ) x→0 X趋向于0
lim(Sin(x+2)分之(x²-x-6)),x趋向于-2求极限
求极限,x趋向于0,lim(x的平方/(sin(x/3)的平方))求极限,x趋向于0,lim(x^2/(sin(x/3)^2))
lim(1+3x)^(2/x)x趋向于零
高等数学的极限问题 lim(x趋向于0)[ln(|sin(x)| - ln(|x|)] 怎么求? 谢谢
当x趋向于0的时候,求lim{[ln(1+x^2)]/(sin(1+x^2)]}的极限
lim ln(sinx/x)的极限.x趋向于0
lim(x趋向于0+)x^tanx 求极限?