lim(1-(cosx)^3)/(x*sin2x)怎么做?

x趋于0 lim sinx-tanx/x^3=lim sinx/x×(cosx-1)/(x^2×cosx)是怎么通分的?x趋于0 lim sinx-tanx/x^3=lim sinx/x×(cosx-1)/(x^2×cosx)thank you .证明当x→0时,[√(1+xsinx)-√(cosx)]～(3/4)x^2.当x→0时,[√(1+xsinx)-√(cosx)]～(3/4)x^2 lim[√(1+xsinx)-√(cosx)]/[(3/4)x^2] =lim(1+xsinx-cosx)/{[√(1+xsinx)+√(cosx)][(3/4)x^2]} =(2/3)lim(1+xsinx-cosx)/(x^2) =(2/3)lim(sinx+xcosx+s lim(x—0) (1-cosx)/x lim(1-(cosx)^3)/(x*sin2x)怎么做? 求Lim(x→0)(sinx/x)^(cosx/1-cosx) 求极限lim(x→3)cosx lim(x_sin)/(3x+2cosx) lim(1-cosx)x趋向0, lim(x→0)(1/cosx)=? 为什么lim sinx/(x-π) =lim cosx/1 lim {(cosx)^(1/2)-(cosx)^(1/3)}/ (sinx)^2 x趋近于0 lim {(cosx)^(1/2)-(cosx)^(1/3)}/ (sinx)^2 x趋近于0 lim(cosx)^(1/(1-cosx)).x趋向于0 大数lim(cosx)^(1/(1-cosx)).x趋向于0 请问高手 x趋近于0 lim (sinx-x*cosx)/(sinx)^3 能不能这样计算原式=lim sinx/(sinx)^3-lim (x*cosx)/(sinx)^3=lim 1/(sinx)^2-lim cosx/(sinx)^2=lim (1-cosx)/(sinx)^2=lim (x^2/2)/(x^2)=1/2,如果可以为何与利用麦克劳林公式所得 求lim(1-cosx)/x^2求lim(1-COSX)/X^2X→0 求极限lim(x->0) 1/x^3 {[(2+cosx)/3]^x-1}求极限lim(x->0)1/x^3 {[(2+cosx)/3]^x-1} 1.lim ([x]-|x|)x->1-2.lim (1-cosx)/xx->派/3这道题的答案是3/(2派)