lim(x_sin)/(3x+2cosx)

lim(x_sin)/(3x+2cosx) 求极限lim(x+3)(2+cosx)/(x^2+x) x趋于0 lim sinx-tanx/x^3=lim sinx/x×(cosx-1)/(x^2×cosx)是怎么通分的?x趋于0 lim sinx-tanx/x^3=lim sinx/x×(cosx-1)/(x^2×cosx)thank you 求极限lim(x→3)cosx lim {(cosx)^(1/2)-(cosx)^(1/3)}/ (sinx)^2 x趋近于0 lim {(cosx)^(1/2)-(cosx)^(1/3)}/ (sinx)^2 x趋近于0 请问高手 x趋近于0 lim (sinx-x*cosx)/(sinx)^3 能不能这样计算原式=lim sinx/(sinx)^3-lim (x*cosx)/(sinx)^3=lim 1/(sinx)^2-lim cosx/(sinx)^2=lim (1-cosx)/(sinx)^2=lim (x^2/2)/(x^2)=1/2,如果可以为何与利用麦克劳林公式所得 求lim(1-cosx)/x^2求lim(1-COSX)/X^2X→0 求极限lim(x->0) 1/x^3 {[(2+cosx)/3]^x-1}求极限lim(x->0)1/x^3 {[(2+cosx)/3]^x-1} 1.lim ([x]-|x|)x->1-2.lim (1-cosx)/xx->派/3这道题的答案是3/(2派) 极限lim(2x^2+x)(sinx+cosx)/x^3-2x+1= 数学分析中求极限问题：lim （2x-3cosx）/5xlim（ 2x-3cosx）/5x lim(x^3+1)(3+cosx)/2x^4-1(x趋向无穷大)的极限 lim x趋于0时：[（2+cosx/3)^x - 1] / x^3 x趋于无穷,求lim(x+3cosx)/(3x-2sinx) lim {[(1+2x)^1/2(1-cosx)]/x^3}=?x→0 lim[(1/(sinx)^2)-(cosx)^2/x^x] x接近于0答案是4/3 求极限lim(sinx^3-x)/(cosx^2+x) x－＞无穷大