求lim(1-cosx)/x^2求lim(1-COSX)/X^2X→0

求lim(1-cosx)/x^2求lim(1-COSX)/X^2X→0 求极限lim (e^x^2)/cosx-1 区域0 求Lim(x→0)(sinx/x)^(cosx/1-cosx) 求极限 lim x->0 1-cosx / 2x^2lim x->0 1-cosx / 2x^2 求lim（x-x*cosx)/(x-sinx) 求极限lim(x+3)(2+cosx)/(x^2+x) 已知lim(x→0) f(x)/(1-cosx) =2 求lim(x→0) [1+f(x)]^½ 求极限lim(x→3)cosx 求极限lim(x→0)x²/1-cosx 求lim(x->0+) x/[根号(1-cosx)]的极限, 求极限 lim x-0 1-cosx / x-sinx 求LIM(1-COSX)/X*SINX X趋近于0 求极限lim(x→0)(cosx-(1/x)) 求极限lim[cosx-e^(-x^2/2)]/x^4 其中x趋向于0.我的做法为什么错了：lim[cosx-e^(-x^2/2)+1-1]/x^4=lim[cosx-1-e^(-x^2/2)+1]]/x^4=lim[-(1-cosx)-(e^(-x^2/2)-1)]]/x^4=lim-(1-cosx)/x^4-lim(e^(-x^2/2)-1)/x^4=lim-1/2x^2/x^4-lim-x^2/x^4=0就是 求极限lim(x->0) 1/x^3 {[(2+cosx)/3]^x-1}求极限lim(x->0)1/x^3 {[(2+cosx)/3]^x-1} lim极限趋向于0+求x/√(1-cosx) lim(√1+cosx)/sinx x趋于π+ 求极限 数学求极限lim x→0 ( x3/1-cosx)