已知sina+sinb+siny=0,cosa+cosb+cosy=0,求cos(b-y)的值
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已知sina+sinb+siny=0,cosa+cosb+cosy=0,求cos(b-y)的值已知sina+sinb+siny=0,cosa+cosb+cosy=0,求cos(b-y)的值已知sina
已知sina+sinb+siny=0,cosa+cosb+cosy=0,求cos(b-y)的值
已知sina+sinb+siny=0,cosa+cosb+cosy=0,求cos(b-y)的值
已知sina+sinb+siny=0,cosa+cosb+cosy=0,求cos(b-y)的值
sina+sinb+siny=0
-sina=sinb+siny
两边平方:
(sina)^2=(sinb)^2+2sinbsiny+(siny)^2--------1
cosa+cosb+cosy=0
-cosa=cosb+cosy
两边平方:
(cosa)^2=(cosb)^2+2cosbcosy+(cosy)^2--------2
1+2:
2(sinbsiny+cosbcosy)=-1
2cos(b-y)=-1
cos(b-y)=-1/2
正确
sina=-(sinb+siny)
cosa=-(cosb+cosy)
然后根据(sina)^2+(cosa)^2=1
得到:
(sinb+siny)^2+(cosb+cosy)^2=1
化简得到:
2+2cosbcosy+2sinbsiny=1
即2cos(b-y)=-1
即cos(b-y)=-1/2
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