x+y/2=2y-z/3=2 x-3y+z=10
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/26 18:24:59
x+y/2=2y-z/3=2x-3y+z=10x+y/2=2y-z/3=2x-3y+z=10x+y/2=2y-z/3=2x-3y+z=10x+y/2=2y-z/3=2*6后=3x+3y=4y-2z=1
x+y/2=2y-z/3=2 x-3y+z=10
x+y/2=2y-z/3=2 x-3y+z=10
x+y/2=2y-z/3=2 x-3y+z=10
x+y/2=2y-z/3=2
*6后=3x+3y=4y-2z=12
得x+y=4①
2y-z=6②
①-②=x-y+z=-2③
x-3y+z=10 ④
④-③=-2y=12
y=-6
代入x+y/2=2得x=10
代入2y-z/3=2得z=-18
x+y/2=2y-z/3=2
即x+y=4,2y-z=6
两式相减,x-y+z=-2
x-3y+z=10 ,x-y+z=-2
两式相减,-2y=12,则y=-6
将y=-6代入x+y=4,2y-z=6,
解得x=10,z=-18
所以,方程的解为x=10,y=-6,z=-18
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
证明 :x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0
x/2=y/3=z/5 x+3y-z/x-3y+z
x+2y=3x+2z=4y+z 求x:y:z
x+y/2=z+x/3=y+z/4 x+y+z=27
若x+y+z=3y=2z,则x/x+y+z=?
分式加减的几道题目求速度1 .(x+y)²/(x-z)(y-z) - (y+z)²/(x-z)(y-z) = 2.2x+3y/x-y+2y/y-x-3y/x-y=
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
已知x,y,z 大于0,x+y+z=2,求证 xz/y(y+z)+zy/x(x+y)+yx/z(z+x)大于等于2/3
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
x+y+z=6 x+2y+3z=14 y+1=z
X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z
设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值