如果x/2=y/7=z/5,xyz不等于0,求x+y+z/3x-y的值
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如果x/2=y/7=z/5,xyz不等于0,求x+y+z/3x-y的值如果x/2=y/7=z/5,xyz不等于0,求x+y+z/3x-y的值如果x/2=y/7=z/5,xyz不等于0,求x+y+z/3
如果x/2=y/7=z/5,xyz不等于0,求x+y+z/3x-y的值
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如果x/2=y/7=z/5,xyz不等于0,求x+y+z/3x-y的值
由x/2=y/7=z/5得出,y=7x/2,z=5x/2,x+y+z=x+7x/2+5x/2=7x,3x-y=-x/2,所以原式=-14
不懂
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