x(x-1)-4(1-x)的平方

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x(x-1)-4(1-x)的平方x(x-1)-4(1-x)的平方x(x-1)-4(1-x)的平方x(x-1)-4(1-x)^2=x(x-1)-4(x-1)^2=(x-1)[x-4(x-1)]=(x-1

x(x-1)-4(1-x)的平方
x(x-1)-4(1-x)的平方

x(x-1)-4(1-x)的平方
x(x-1)-4(1-x)^2
=x(x-1)-4(x-1)^2
=(x-1)[x-4(x-1)]
=(x-1)(-3x+4)
如果您要问x(x-1)-4(1-x)^2=0
那么X1=1
X2=4/3

楼上的回答是正确的~~~~

x(x-1)-4(1-x)²=x(x-1)-4(x-1)²=(x-1)(x-4(x-1))=(x-1)(x-4x+4)==(x-1)(4-3x)