求sin(x)与cos(x)在【0,2π】内交点.

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求sin(x)与cos(x)在【0,2π】内交点.求sin(x)与cos(x)在【0,2π】内交点.求sin(x)与cos(x)在【0,2π】内交点.sinx=cosx所以,tanx=1解得,x=π/

求sin(x)与cos(x)在【0,2π】内交点.
求sin(x)与cos(x)在【0,2π】内交点.

求sin(x)与cos(x)在【0,2π】内交点.
sinx=cosx
所以,tanx=1
解得,x=π/4,或 x=5π/4
交点坐标为(π/4,根号2/2),(5π/4,- 根号2/2)

交点俩个,由图像知道,
sinx=cosx
所以,tanx=1
解得,x=π/4,或 x=5π/4
交点坐标为(π/4,根号2/2),(5π/4,- 根号2/2)
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