求Lim (2sin^n x+3cos^n x)∕(sin^n x+cos^n x) ,0≤x≤π/2n趋于无穷大

求Lim (2sin^n x+3cos^n x)∕(sin^n x+cos^n x) ,0≤x≤π/2n趋于无穷大 求lim(cos^n次方x-sin^n次方x)/(cos^n次方x+sin^n次方x) X趋向于π,求lim((sin^2 X)/()1+cos^3 X) 如何求 lim(n→∞)cos(x/2)cos(x/4)...cos(x/2n) 求lim (sin^2x+x)/(cos^2x-x) x趋向于无穷 求函数的极限lim((x→x/2)cosx)/(cos(x/2)-sin(x/2)) 求 lim(x→∞)[sin(2/x)+cos(1/x)]^x的极限. lim(sin(x^2*cos(1/x)))/x怎么做? lim[n:∞,(x^(2)+2x-sin(x))/(2x^(2)+cos(x))] 这道题目的如何解? 利用无穷小的性质求极限lim(x→+∞)[(n^2+1)/n^3]sin(n!)= lim x->无穷大 （n-sin n）/(n+cos n)=? 求极限(sin(2/n)+cos(3/n))^(-n) lim 2^n *sin(x/2^n)n→∞求极限 lim(n→∞){2^n[sin(x/2^n)]}求详细过程,谢谢! lim(n→∞) (cos x/n)^n^2 求lim(x->&无穷)sinn/n,求lim(x->无穷)sin(1/n) 用洛必达法则求几个极限（有图）~用洛必达法则求以下极限（见图）lim [(e^x)-1/sin（5x)]x->0lim [1-cos(5x)/1-cos(7x)]x->0lim x->0 [(8^x-7^x-1)/(x^2)-1]lim [1-(6/x)]^x x->0 lim 7cos(3x)sec(9x)x->∞（搞错了~应该是>/ 已知sin(x)+3cos(x)=2,求sin(x)-cos(x)/sin(x)+cos(x)=?