化简(log4(3)+log8(3))(log3(2)+log9(2))(log4(3)+log8(3))(log3(2)+log9(2))=(lg3/lg4+lg3/lg8)(lg2/lg3+lg2/lg9)=5lg3/6lg2X3lg2/2lg3=5/6X3/2=5/4可是是怎样从第一步到第二步的?
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/01 07:05:09
化简(log4(3)+log8(3))(log3(2)+log9(2))(log4(3)+log8(3))(log3(2)+log9(2))=(lg3/lg4+lg3/lg8)(lg2/lg3+lg2
化简(log4(3)+log8(3))(log3(2)+log9(2))(log4(3)+log8(3))(log3(2)+log9(2))=(lg3/lg4+lg3/lg8)(lg2/lg3+lg2/lg9)=5lg3/6lg2X3lg2/2lg3=5/6X3/2=5/4可是是怎样从第一步到第二步的?
化简(log4(3)+log8(3))(log3(2)+log9(2))
(log4(3)+log8(3))(log3(2)+log9(2))
=(lg3/lg4+lg3/lg8)(lg2/lg3+lg2/lg9)
=5lg3/6lg2X3lg2/2lg3
=5/6X3/2
=5/4
可是是怎样从第一步到第二步的?
化简(log4(3)+log8(3))(log3(2)+log9(2))(log4(3)+log8(3))(log3(2)+log9(2))=(lg3/lg4+lg3/lg8)(lg2/lg3+lg2/lg9)=5lg3/6lg2X3lg2/2lg3=5/6X3/2=5/4可是是怎样从第一步到第二步的?
4^a=3
公式1过程两边取lg()的对数:
lg4^a=lg3
a=lg3/lg4(公式1)
公式2过程两边取log4()的对数:
log4(4^a)=log4(3),又因为log4(4^a)=a*log4(4)=a*1=a
所以a=log4(3)(公式2)
所以 log4(3)=lg3/lg4 这是基本的公式,直接就可以利用的
化简(log4(3)+log8(3))(log3(2)+log9(2))
log4(3)+log8(3) 怎么算
log4(3)+log8(3) 怎么相加?
(log4(3)+log8(3))*log3(2)
log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8( 8^(2/3) )怎么得出来的?
(log3^2 + log9^4)×(log4^3 + log8^3)
(log3 2+log9 2)*(log4 3+log8 3)求值
计算log9(根号2)*[log4(3)+log8(3)]
计算:(log4 3+log8 3)×log9 √2=?
求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)
(log4(3)+log8(3))*(log3(2)+log8(2))-log1/2(^4√32)=?..
(log4(3)+log8(3))(log3(2)+log9(2))-log4(3)×log1/3(四次根号32)
化简:(log2(3)+log4(9)+log8(27)+…+log2n(3^n))*log2(8的n次方根)
急 求 (log3 2+log9 2)-(log4 3+log8 3)求 (log3 2+log9 2)-(log4 3+log8 3)
解该式:(log4(3)+log8(3))*(lg2/lg3)log4(3)是指以4为底
log3 4*log4 8*log8 m=log4 16,则m为[ ]其中3、4、8、4为底数.
[log4(3)+log8(3)]*log3(2)答案是1/3么
求(log3^2 + log9^2)×(log4^3 + log8^3)的值.请给出过程,谢谢!