an为等差数列,a4+a7+a10=17,a4+a5+a6...+a14=77,ak=13,求k

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/25 13:59:19
an为等差数列,a4+a7+a10=17,a4+a5+a6...+a14=77,ak=13,求kan为等差数列,a4+a7+a10=17,a4+a5+a6...+a14=77,ak=13,求kan为等

an为等差数列,a4+a7+a10=17,a4+a5+a6...+a14=77,ak=13,求k
an为等差数列,a4+a7+a10=17,a4+a5+a6...+a14=77,ak=13,求k

an为等差数列,a4+a7+a10=17,a4+a5+a6...+a14=77,ak=13,求k
若m+n=p+q则am+an=ap+aq;
a4+a10=2a7 则3a7=17;a7=17/3;
a4+a5+a6+···+a14=10*a9+a9=11a9=77 则a9=7;
a9-a7=2d=7-17/3=4/3
d=2/3;a1=5/3
ak=a1+(k-1)d=5/3+(k-1)*2/3=13
k=18
希望采纳#^_^#
祝学习进步!

3a7=17;11a9=77; d=2/3; a1=5/3
5/3+(k-1)2/3=13
k=18