解不等式logx(5x-1)≥logx(5x+1)

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解不等式logx(5x-1)≥logx(5x+1)解不等式logx(5x-1)≥logx(5x+1)解不等式logx(5x-1)≥logx(5x+1)当0logx(5x-1)≥logx(5x+1)要使

解不等式logx(5x-1)≥logx(5x+1)
解不等式logx(5x-1)≥logx(5x+1)

解不等式logx(5x-1)≥logx(5x+1)
当 0

logx(5x-1)≥logx(5x+1)
要使不等式有意义,则x>0且 x≠1 5x+1>0 5x-1>0 ∴x>1/5且 x≠1
∵5x-1≤5x+1 logx(5x-1)≥logx(5x+1)
∴0<x<1
∴1/5<x<1

解不等式logx(5x-1)≥logx(5x+1),1/5