求函数y=sin(π/3+4x)+cos(4x-π/6)的单调区间

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求函数y=sin(π/3+4x)+cos(4x-π/6)的单调区间求函数y=sin(π/3+4x)+cos(4x-π/6)的单调区间求函数y=sin(π/3+4x)+cos(4x-π/6)的单调区间y

求函数y=sin(π/3+4x)+cos(4x-π/6)的单调区间
求函数y=sin(π/3+4x)+cos(4x-π/6)的单调区间

求函数y=sin(π/3+4x)+cos(4x-π/6)的单调区间
y=sin(π/3+4x)+cos(4x-π/6)
=sin(π/3+4x)+sin(π/2-4x+π/6)
=sin(π/3+4x)+sin(2π/3-4x)
=2sin[(π/3+4x+2π/3-4x)/2]cos[(π/3+4x-2π/3+4x)/2]
=2sin(π/2)cos(4x-π/6)
=2cos(4x-π/6)
当2kπ