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已知0已知0已知0tan(α+π/4)=(1+tana)/(1-tana)=3+2√2tana=√2/2(1-cos2α)/sin2α=(1-(1-2sin^2a))/2sinacosa=sins/c
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已知0<α<π/2,tan(α+π/4)=3+2根号2,则(1-cos2α)/sin2α=
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tan(α+π/4)=(1+tana)/(1-tana)=3+2√2
tana=√2/2
(1-cos2α)/sin2α
=(1-(1-2sin^2a))/2sinacosa
=sins/cosa
=tana=√2/2