已知:x = 1/2+√3 ,xy=1,则 x²y-xy²/x²-y².
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已知:x=1/2+√3,xy=1,则x²y-xy²/x²-y².已知:x=1/2+√3,xy=1,则x²y-xy²/x²-y
已知:x = 1/2+√3 ,xy=1,则 x²y-xy²/x²-y².
已知:x = 1/2+√3 ,xy=1,则 x²y-xy²/x²-y².
已知:x = 1/2+√3 ,xy=1,则 x²y-xy²/x²-y².
解
x=1/(2+√3)=(2-√3)/(2+√3)(2-√3)=2-√3
∵xy=1
∴y=1/x=2+√3
∴原式
=xy(x-y)/(x-y)(x+y)
=xy/(x+y)
=1/(2+√3+2-√3)
=1/4
x/y=3
∴x=3y
∴原式
=(9y²+6y²-3y²)/(9y²-3y²+y²)
=12y²/(7y²)
=12/7
已知:x = 1/2+√3 ,xy=1,则 x²y-xy²/x²-y².
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