1/1×3+1/2×4+1/3×5+……1/n(n+2),求和
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1/1×3+1/2×4+1/3×5+……1/n(n+2),求和1/1×3+1/2×4+1/3×5+……1/n(n+2),求和1/1×3+1/2×4+1/3×5+……1/n(n+2),求和1/n(n+2
1/1×3+1/2×4+1/3×5+……1/n(n+2),求和
1/1×3+1/2×4+1/3×5+……1/n(n+2),求和
1/1×3+1/2×4+1/3×5+……1/n(n+2),求和
1/n(n+2)
=1/2*[1/n-1/(n+2)]
1/1×3+1/2×4+1/3×5+……1/n(n+2),
=1/2*[1-1/3+1/2-1/4+1/3-1/5+.+1/(n-1)-1/(n+1)+1/n-1/(n+2)]
=1/2*[1+1/2-1/(n+1)-1/(n+2)]
=3/4-1/2(n+1)-1/2(n+2)
首先观察找规律
1/n(n+2)=1/2[1/n-1/(n+2)]
所以1/1*3+1/2*4+1/3*5+.....+1/n(n+2)
=1/2[1/1-1/3+1/2-1/4+1/3-1/5+...+1/n-1/(n+2)
=1/2[1+1/2-1/(n-1)-1/(n-2)]
=3/8-1/2(n-1)-1/2(n-2)
(1+1/2)(1+1/3)(1+1/4)(1+1/5)……(1+1/2005)(1+1/2006)=?
1×2分之1+2×3分之1+3×4分之1+4×5分之1…………+199×200分之1
数学必修5数列求和1+(1/1+2)+(1/1+2+3)+(1/1+2+3+4)+……+(1/1+2+3+……+n)
1×2×3×4+1=5^2…………………………………………初一数学,(平方公式).1×2×3×4+1=5^2;2×3×4×5+1=11^2;3×4×5×6+1=19^2;…………………………求结论,并计算:2000×2001×2002×2003+1=?
简算 1+2+3+4+5…………+49+50等于多少
(1+1×3/1)(1+2×4/1)(1+3×5/1)……(1+99×101/1)
1/1×3+1/3×5+1/5×7+…………+1/49×51和1/2×4+1/4×6+1/6×8+…………1/48×50接着 还有1/1+2 + 1/1+2+3 +……+ 1/1+2+3+……+100我明天上课用
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1+2+3+4……+66+65+64……+1=
1+2+3+4…………+49+50+49…+4+3+2+1=?
1+2+3+4+……+99999+100000
计算1×2×3+2×3×4+3×4×5+…….+100×101×102?
【1/2+1/3+1/4+……+1/50】+【2/3+2/4+2/5+……+2/50】+【3/4+3/5+……+3/50】+……*【48/49+48/50】+49/50怎样简便运算
1/2×2/3+1/3×2/4+1/4×2/5+……+1/99×2/100 计算
1/1×2×3×4+1/2×3×4×5+…+1/7×8×9×10=
1+2+3+4+5…+10000=几
1/1×2+1/2×3+1/3×4+……+1/2002×2003.
1/3平方-1+1/5平方-1 +1/7平方-1 +…… 1/(2n+1)平方-1+……=( )