1.sin^2(1°)+sin^2(2°)+sin^2(3°)+……+sin^2(89°)+sin^2(90°).2.已知tanα100°=k,则sin80°=_______?3.已知α是锐角,2tan(π-α)-3cos(π/2+β)+5=0,tan(π+α)+6sin(π+β)-1=0.则sinα=______?
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/23 07:24:06
1.sin^2(1°)+sin^2(2°)+sin^2(3°)+……+sin^2(89°)+sin^2(90°).2.已知tanα100°=k,则sin80°=_______?3.已知α是锐角,2tan(π-α)-3cos(π/2+β)+5=0,tan(π+α)+6sin(π+β)-1=0.则sinα=______?
1.sin^2(1°)+sin^2(2°)+sin^2(3°)+……+sin^2(89°)+sin^2(90°).
2.已知tanα100°=k,则sin80°=_______?
3.已知α是锐角,2tan(π-α)-3cos(π/2+β)+5=0,tan(π+α)+6sin(π+β)-1=0.则sinα=______?
1.sin^2(1°)+sin^2(2°)+sin^2(3°)+……+sin^2(89°)+sin^2(90°).2.已知tanα100°=k,则sin80°=_______?3.已知α是锐角,2tan(π-α)-3cos(π/2+β)+5=0,tan(π+α)+6sin(π+β)-1=0.则sinα=______?
1.设A=sin^2(1°)+sin^2(2°)+sin^2(3°)+……+sin^2(89°)+sin^2(90°).① 则
A=sin^2(90°)+sin^2(89°)+sin^2(88°)+……+sin^2(2°)+sin^2(1°)
=sin^2(90°)+cos^2(1°)+cos^2(2°)+……+cos^2(88°)+cos^2(89°).②
把①②错位相加,即
2A=sin^2(90°）+[sin^2(1°)+cos^2(1°)]+[sin^2(2°)+cos^2(2°)]
+[sin^2(3°)+cos^2(3°)]+……+[sin^2(89°)+cos^2(89°)]+sin^2(90°)
=1+89*1+1=91
A=91/2
2.由sin(180°-A)=sinA,cos(180°-A)=-cosA,得tan(180°-A)=-tanA.则
tan80°=tan(180°-100°)=-tan100°=-k.
sin^2(80°)/[1-sin^2(80°)]=k^2,解得sin80°=k/(1+k^2的算术平方根)
3.由cos(90°+A)=-sinA,sin(180°+A)=-sinA,tan(180°-A)=-tanA tan(180°+A)=tanA .得
2tan(π-α)-3cos(π/2+β)+5=0 即 -2tanα+3sinβ+5=0 ①
tan(π+α)+6sin(π+β)-1=0 即 tanα-6sinβ-1=0 ②
①*2+②得tanπα=3,则 sinα=3/(10的算术平方根)
1.sin^2(1)+sin^2(89)=1,sin^2(2)+sin^(88)=16……，sin^2(44)+sin^2(46)=1
共44,sin^2(45)=1/2,sin^2(90)=1,总共45。5 （“度”不会打,抱歉。下同）
2。sin80=sin100,sin80=tan100/根号（1+tan^2(100)=k/根号(1+k^2)