一个质量mA为4kg的木板A放在水平面C上,木板与水平面间的动摩擦因数u=0.24,木板右上端放着质量m B为1.0k的小物块B(视为质点),它们均处于静止状态,木板A 突然受到水平向右的瞬时冲量I=12N.s
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一个质量mA为4kg的木板A放在水平面C上,木板与水平面间的动摩擦因数u=0.24,木板右上端放着质量m B为1.0k的小物块B(视为质点),它们均处于静止状态,木板A 突然受到水平向右的瞬时冲量I=12N.s
一个质量mA为4kg的木板A放在水平面C上,木板与水平面间的动摩擦因数u=0.24,木板右上端放着质量m B为1.0k的小物块B(视为质点),它们均处于静止状态,木板A 突然受到水平向右的瞬时冲量I=12N.s作用后开始运动.当小物块B滑落木板时,木板的动能EKA=8.0J,小物块的动能EKB=0.50J,重力加速度取10m/s2.求:
1)瞬时冲量作用结束时木板的速度v0;
2)木板的长度L
一个质量mA为4kg的木板A放在水平面C上,木板与水平面间的动摩擦因数u=0.24,木板右上端放着质量m B为1.0k的小物块B(视为质点),它们均处于静止状态,木板A 突然受到水平向右的瞬时冲量I=12N.s
1)I=mB*V0
V0=I/mB=12 / 1=12 m/s
2)对B,F*SB=EkB
F* t =mB*VB
对A,[ F+u*(mA+mB*)g ]*SA=(mA*V0^2 / 2)-EkA
[ F+u*(mA+mB*)g ]* t =mA*(V0-VA)
SA-SB=L
以上五式联立,得
L=21.3125米 文字输入有限.
3 rockets overnight turned young military
McHale
The key reason why a lot of competition for your Rockets who select McHale, took a pricy to him and the young players go along nicely, and good...
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3 rockets overnight turned young military
McHale
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