log2(x^2-2x=29)>=5 算x的值log2(x^2-2x-29)>=5 中间是减号,打错啦
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/27 21:58:51
log2(x^2-2x=29)>=5算x的值log2(x^2-2x-29)>=5中间是减号,打错啦log2(x^2-2x=29)>=5算x的值log2(x^2-2x-29)>=5中间是减号,打错啦lo
log2(x^2-2x=29)>=5 算x的值log2(x^2-2x-29)>=5 中间是减号,打错啦
log2(x^2-2x=29)>=5 算x的值
log2(x^2-2x-29)>=5 中间是减号,打错啦
log2(x^2-2x=29)>=5 算x的值log2(x^2-2x-29)>=5 中间是减号,打错啦
∵ x^2-2x-29>0√
log2(x^2-2x-29)≥5=log2[2^5)
即 x^2-2x-29≤ 32
∴x1+√30,1-√62≤ x≤1+√62
∴log2(x^2-2x-29)≥5的解集为:
{x:1-√62≤ x
log[2](x^2-2x-29)>=5
∵2>0
∴log[2](x^2-2x-29)单调递增
x^2-2x-29≥2^5
x^2-2x-61≥0
x≤1-√62,或x≥1+√62
∵ x^2-2x-29>0
log2(x^2-2x-29)≥5=log2[2^5)
即 x^2-2x-29≥ 32
∴x^2-2x-61≥0
∴(x-1)^2≥62
∴x≤1-√62,或x≥1+√62
log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)
log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)
log2 4+log2 (x+2)怎么算?log2 4+log2 (x+2)=log2 (4x+8)
解2log2^(x-5)=log2^(x-1)+1
log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
log2(x-2)=log4(5-x)
log2(2x)*log2(x)=2 x=?
f(x)=log2(x/8)*log2(2/x)
[log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204
log2(x^2-2x=29)>=5 算x的值log2(x^2-2x-29)>=5 中间是减号,打错啦
求导 y=log2(x^2)-log2(x)
求解log2(3x)=log2(2x+1)
解方程log2(2-x)=log2(x-1)+1
log2^(x^log2^x)=?
解方程log2(x+14)-log2(x+6)=3-log2(x+2)
log2(x^2-3)=5 计算
求函数f(x)=2+log2^x+5/log2^x,(0
求函数f(x)=2+log2 x+5/log2 x的最值(0