化简cos^4 a-(1/4)cos^2 2a-(1/2)cos 2a
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化简cos^4a-(1/4)cos^22a-(1/2)cos2a化简cos^4a-(1/4)cos^22a-(1/2)cos2a化简cos^4a-(1/4)cos^22a-(1/2)cos2acos^
化简cos^4 a-(1/4)cos^2 2a-(1/2)cos 2a
化简cos^4 a-(1/4)cos^2 2a-(1/2)cos 2a
化简cos^4 a-(1/4)cos^2 2a-(1/2)cos 2a
cos^4 a-(1/4)cos^2 2a-(1/2)cos 2a
=[(1/2)(cos2a+1)]²-(1/4)cos²2a-(1/2)cos2a
=(1/4)(cos²2a+2cos2a+1)-(1/4)cos²2a-(1/2)cos2a
=(1/4)cos²2a+(1/2)cos2a+1/4-(1/4)cos²2a-(1/2)cos2a
=1/4
=1/2*2*cos[(2a-B 2a B)/2]sin[(2a-B-2a-B)/2] =cos[(4a/2]sin[(-2B)/2] =cos2asin(-B) =-cos2asinB cos(a-π/6) sina=4√3
化简 1-sin^4a-cos^4a/cos^2a-cos^4a
化简(1-sin^6 a-cos^6 a)/(cos^2 a-cos^4 a)==
化简cos^4 a-(1/4)cos^2 2a-(1/2)cos 2a
化简(2cos^2A-1)/2tan(π/4-A)cos^2(π/4-A)
5cos^2a+4cos^2β=4cosα则cos^2a+cos^2β
由cos(a+b)=cos a cos b-sin a sin b cos(a-b)=cos a cos b+sin a sin b解题设a为锐角,证:1、2分之根3乘cos a + 2分之1乘sin a=cos(6分之π-a)2、cos a-sin a=根号2cos(4分之π+a)
证明sin(4A)sin(2A)(1-cos(2A)) cos(4A)cos(2A)(1 cos(2A))=cos(2A)(1 cos(6A))应该是sin4Asin2A(1-cos2A) + cos4Acos2A(1+cos2A)=cos2A(1+cos6A)
已知sin(3π+a)=1/4,求[cos(π+a)]/{cosa[cos(π+a)-1]}+[cos(a-2π)]/[cos(a+2π)cos(π+a)+cos(-a)]的值要具体过程
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化简cos(π/4-a)cos(π/4+a)
化简cos(π/4-a)cos(π/4+a)=
化简1-cos^4a-sin^4a/1-cos^6-sin^6acos^6应为cos^6a
证明 sin^4a-cos^4a=1-2cos^2asin^4a-cos^4a=1-2cos^2a
化简 :1+ 2cos^2 a - cos 2 a
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1-sin2a-cos^2(a-π/4)
化简1+cos(a-360)cos(a-180)-2cos^2a