求1/(y^2-x^2-5*x^4)+1/(y^2-2*x^2-5*x^2)=1在 x=0:0.1:10上的y值（matlab求解）

求y=(5x-1)/(4x+2) (x (x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5) x^2-x+y^2+2y+5/4=0 求x^-1+y^0 4x-3y=5 x^2+y^2=1 求x,y 3x+4y-5=0 x^2+y^2=1求x.y {(x+y)/2+(x-y)/3=1,(x+y)-5(x-y)=2.求x=?,y=? 若x^5+x^4y+x^4+x+y+1=0,且3x+2y=1,求x,y的值 y=x^5+√x+1/x^3 ,求导数结果是y’=2x-5/2x^-7/2-3x^-4,对y求导数 已知x²+y²+5=2x+4y,求代数式（2x²-（x+y)(x-y))x((x+y-1)(x-y+1)+(1-2y)) 已知:【(x²+y²)-(x-y)²+2y(x-y)】/4y=1,求4x/4x²-y²-1/2x+y 已知x=1/3,y=-1/2,求代数式x-(x+y)+(x+2y)-(x+3y)+(x+4y)-(x+5y)+...-(x+2009y)的值. 已知x=1/3,y=-1/2,求代数式x-(x+y)+(x+2y)-(x+3y)+(x+4y)-(x+5y)+...-(x+2009y)的值. 求值域 1,y=(x+2)/(x*x+3x+6) 2,y=3x/(x*x+4) 已知x-y=1,求[(x+2y)^2+(2x+y)(x-4y)-3(x+y)(x-y)]除以y的值大神们帮帮忙 已知x-y=1,求[(x+2y)²+(2x+y)(x-4y)-3(x+y)(x-y)]÷y的值 求值域,Y=5x-1/4x+2 y=5x-1／4x+2,求值域 三分之x-2y-二分之x+2y=-1,5(x-2y)-4(x+2y)=-1求x和y的值