lim(x趋向0) 1-cos2x/xsinx
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/22 12:21:06
lim(x趋向0)1-cos2x/xsinxlim(x趋向0)1-cos2x/xsinxlim(x趋向0)1-cos2x/xsinxlim2sinx/x=2
lim(x趋向0) 1-cos2x/xsinx
lim(x趋向0) 1-cos2x/xsinx
lim(x趋向0) 1-cos2x/xsinx
lim2sinx/x=2
lim(x趋向0) 1-cos2x/xsinx
lim(x趋向0)(1-cos2x)/xsinx怎么解?
lim x趋向0 [x(1-cos2x)]/(5x-sin5x)?知道答案是12/125,
lim(x趋向0)[1-cos(1-cos2x)]/x^4怎么解?
lim(x趋向0)[1-cos(1-cos2x)]/x^4怎么解?
求极限:lim(x趋向0) [1-cosx(cos2x)^1/2(cos3x)^1/3]/[ln(1+x)-x]
求极限 (1) x趋向x/6 lim ln(2cos2x) (2) x趋向0 lim(e^x-1)/x (3) x趋向0 lim[ln(a+x)-lna]/x (a>0)(4) x趋向a lim(sinx-sina)/(x-a)
(x趋向于0)lim(cosx-cos2x)/x^2
求极限lim(x~0)((e^x+e^2x+e^3x)/3)^1/xs
lim(1-cosx)x趋向0,
lim(x→0)(1-cos2x)/xsinx
1.x趋向0 lim (cosx-1)/x 2.x趋向0 lim sinx/x
高数求极限,求极限:lim(x趋向0) [1-cosx(cos2x)^1/2(cos3x)^1/3]/[ln(1+x)-x]
x趋向0 lim xcotx
求极限x趋向于0 (1-cos2x)/xsinx
求lim(x→0)〔1-cos2x+tan^2 X〕/xsinx当x趋向于0时,求1减cos2x加tanx的平方再除以x倍的sinx的极限值
x趋向0 lim [ ln (1-x) / (e ^ x-1 ) ]
计算极限 lim(1-x)^1/x x趋向0