不等式[log2(-x)]2>=log2(x2)的解集是
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不等式[log2(-x)]2>=log2(x2)的解集是不等式[log2(-x)]2>=log2(x2)的解集是不等式[log2(-x)]2>=log2(x2)的解集是[log2(-x)]2-log2
不等式[log2(-x)]2>=log2(x2)的解集是
不等式[log2(-x)]2>=log2(x2)的解集是
不等式[log2(-x)]2>=log2(x2)的解集是
[log2(-x)]2-log2((-x)2)>=0
so [log2(-x)]2-2*log2(-x)>=0
so log2(-x)>=2 or log2(-x)<=0
if log2(-x)>=2,-x>=4,x<=-4
if log2(-x)<=0,0<-x<=1,-1<=x<0
so x<=-4 or -1<=x<0
不等式[log2(-x)]2>=log2(x2)的解集是
不等式|2x-log2^x|
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不等式log2(2x-4)
log2(x2-x-2)>log2(2x-2)解不等式
解不等式2log2 (x-4)< log2 (x-2)
不等式log2(2x+3)>log2(x+1)的解集是
解不等式log2(4x+8)>log2(2x+1)
不等式log2 (x+1)
不等式 log2 (-x)
不等式log2(x2-x)
log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
log2^(x^log2^x)=?
已知函数f(x)=log2^ ( x/4 ) ×log2^ (2x) (1)解不等式f(x)>0;(2)当x∈【1,4】时,求f(x)的值域f(x)=log2(2x)×log2(x/4)=[(log2 2)+(log2 x)] ×[(log2 x) -(log2 4)]=[1+(log2 x)] ×[(log2 x) -2]=(log2 x)² - (log2 x) -2
log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)
log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)
解不等式:log2(x^2-x-2)