设A={x|2X^2+aX+2=0},B=[X|X^2+3X+2a=0},且AUB={2,5,0.5},求A∩BX^2是X的2次方

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设A={x|2X^2+aX+2=0},B=[X|X^2+3X+2a=0},且AUB={2,5,0.5},求A∩BX^2是X的2次方设A={x|2X^2+aX+2=0},B=[X|X^2+3X+2a=0

设A={x|2X^2+aX+2=0},B=[X|X^2+3X+2a=0},且AUB={2,5,0.5},求A∩BX^2是X的2次方
设A={x|2X^2+aX+2=0},B=[X|X^2+3X+2a=0},且AUB={2,5,0.5},求A∩B
X^2是X的2次方

设A={x|2X^2+aX+2=0},B=[X|X^2+3X+2a=0},且AUB={2,5,0.5},求A∩BX^2是X的2次方
设A={x|2X^2+aX+2=0,B=[X|X^2+3X+2a=0},AUB={2,5,0.5},
因为AUB={2,5,0.5},所以1）当X=2时对于A,解得
a=-5,对于B解得a=-5.2）当X=5时对于A,解得
a=-52\5,对于B解得a=-20 3)当X=0.5时对于A解得a=-5
对于B解得a=-0.875所以A∩B={x|X=2}
只有a=-5时A=B.所以A∩B={x|X=2}
这题关键在于理解交集与并集的意义了.

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