lim(x→0)=(arctanx-x)/ln(1+2x^3)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/23 09:43:24
lim(x→0)=(arctanx-x)/ln(1+2x^3)lim(x→0)=(arctanx-x)/ln(1+2x^3)lim(x→0)=(arctanx-x)/ln(1+2x^3)说明:此题书写
lim(x→0)=(arctanx-x)/ln(1+2x^3)
lim(x→0)=(arctanx-x)/ln(1+2x^3)
lim(x→0)=(arctanx-x)/ln(1+2x^3)
说明:此题书写错误,应该是“lim(x→0)[(arctanx-x)/ln(1+2x^3)]”.
原式=lim(x->0)[(arctanx-x)'/(ln(1+2x^3))'] (0/0型极限,应用罗比达法则)
=lim(x->0)[-(1+2x^3)/(6(1+x^2))]
=-(1+0)/(6(1+0))
=-1/6.
lim(x→0)=(arctanx-x)/ln(1+2x^3)
lim(下面是x→100 )arctanx=
lim(x趋近于0+)arctanx=?
lim(x+arctanx)/(x-arctanx) (x→∞)
求lim(x→0)arctanx/x的极限,
求极限解题lim(x→∞)=arctanx/x
一.x---->0时,证明lim(arctanx)/x=1
lim(x趋向0)(x-arctanx)/(x-arcsinx)=?
求极限lim(x→0)sinxsin(1/x);lim(x→∞)(arctanx/x)
当x趋向于0+,lim arctanx/lnx=?
lim(n趋近于0)(arctanx)/x
lim(arctanx/sinx) x->0
lim(x→0 )(arctanx/x)^(1/x^2)求极限求lim(x→0 )(arctanx/x)^(1/x^2)
lim(x+sinx)/(3x-arctanx)(x趋于无穷)
证明:arctanx和x是等价无穷小量证明:lim(x→0)arctanx/x=1,即证明arctanx和x是等价无穷小量,用洛必达法则作可以吧?这题好像是0/0求极限的类型
lim(x→∞)arctanx/x的极限
lim(x→+∞)(2/π*arctanx)^x求极限
求极限lim(2/π*arctanx)^x x→∞