怎么证明cos2x/1-sin2x = cosx+sinx/cosx-sinx

来源：学生作业帮助网编辑：六六作业网时间：2025/01/29 08:02:56

怎么证明cos2x/1-sin2x=cosx+sinx/cosx-sinx怎么证明cos2x/1-sin2x=cosx+sinx/cosx-sinx怎么证明cos2x/1-sin2x=cosx+sin

怎么证明cos2x/1-sin2x = cosx+sinx/cosx-sinx
怎么证明cos2x/1-sin2x = cosx+sinx/cosx-sinx

怎么证明cos2x/1-sin2x = cosx+sinx/cosx-sinx
证：
(cosx+sinx)/(cosx-sinx)
=[(cosx+sinx)(cosx-sinx)]/(cosx-sinx)^2
=[(cosx)^2-(sinx)^2]/[(cosx)^2-2sinxcosx+(sinx)^2]
=cos(2x)/(1-2sinxcosx)
=cos(2x)/[1-sin(2x)]

1-cos2x+sin2x/1+cos2x+sin2x=tanx证明题怎么做怎么证明cos2x/1-sin2x = cosx+sinx/cosx-sinx 导数证明sin2x+cos2x=1 证明sin2x+cos2x=1如题证明：(sin2x)^2+2(cos2x)^2=1+(cos2x)^2 1-cos2x+sin2x= 二倍角推导公式tanx=(1-cos2x)/sin2x证明 Cosx+sinx分之1+sin2x+cos2x=2cos 证明 1-cos2x sin2x/1 cos2x sin2x=tanx这道题怎么做 sin2x/cos2x-sin2x怎么变成[sin2x·(1-cos2x)]/cos2x ,是怎么变化的? 求证1+sin2x-cos2x/1+sin2x+cos2x=tanx 证明(sin4x+sin2x)/(cos4x+cos2x)=tan3x如题,这个要怎么证明啊 f(x)=(cos2x-1)/sin2x怎么化简（sin3xsinx）sin2x+（cos3xcosx）cos2x =1/ 2 [（cos2x-cos4x）sin2x+（cos2x+cos4x）cos2x] 是怎么变的根号3 /2 ×sin2x+1/2cos2x=3/5 怎么解cos2x得几啊化简（1+sin2x-cos2x)/(1+sin2x+cos2x) 1-2sinXcosX除以cos2X-sin2X=1-tanx除以1+tanX证明出来（1+cos2x)/2cosx=sin2x/(1-cos2x)